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Solar inverter sizing calculator: DC/AC ratio, clipping losses & the right inverter

Simulates your array hour by hour with NASA weather to show how much energy each inverter size would clip, then recommends the size, the phase and the economic DC/AC ratio.

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How this inverter sizing calculator works

The inverter is usually the one component of a solar system that is deliberately undersized. Panels almost never reach their nameplate power, so an inverter matched one-to-one to the array spends its life partly idle. The real question is: how much energy would a smaller inverter clip, and is the saving worth it? That depends on your climate, orientation and module temperatures, so this calculator answers it by simulation rather than rule of thumb.

It downloads a full year of hourly NASA POWER weather for your location and simulates the array’s DC output hour by hour (sun position, Hay–Davies sky model, incidence-angle losses, cell temperature and your DC losses). It then passes that hourly series through inverters of every standard size, from a DC/AC ratio of 2.0 down to 0.8, applies the conversion efficiency and caps output at each rating. The difference between capped and uncapped energy is the clipping loss. Last, it values the lost energy over the inverter’s life and compares it with the money saved by buying a smaller unit.

The formulas

DC/AC ratio = P_array,STC (kWp) ÷ P_inverter,AC (kW) P_ac(t) = min( P_dc(t) × η_inv , P_inverter ) Clipping loss = Σ_t max(0, P_dc(t) × η_inv − P_inverter) ÷ Σ_t P_dc(t) × η_inv AC current: I = P ÷ V (single-phase) I = P ÷ (√3 × V_LL) (three-phase)

Worked example: 8 kWp in Bucharest

Take the defaults: 8 kWp of TOPCon modules facing south at 30°, 12% DC losses and a 97.5%-efficient inverter. The array’s highest hourly output in 2024 is about 6.5 kW, only 81% of its rating, and 99% of producing hours stay below 5.9 kW.

A 6 kW inverter (DC/AC 1.33) therefore clips just 6 kWh a year (0.1%) and delivers about 10,020 kWh, or 1,253 kWh per kWp. A 5 kW unit (ratio 1.60) would clip 2.1%, roughly 210 kWh a year, and a 4 kW unit 9.2%. With a marginal inverter cost of €120 per kW, energy worth €0.15/kWh and a 12-year inverter life, 6 kW is both the smallest low-loss size and the economic optimum. On a 230 V single-phase connection it draws 26 A. That is above the 16 A limit many grid codes set for single-phase generation, so check whether a three-phase unit is required.

How to read the results

  • Recommended inverter is the smallest standard size that clips at most 0.5% of hourly energy, or the economic optimum if it clips no more than 2%, respecting any grid limit you enter.
  • Clipping loss vs DC/AC ratio shows the knee of the curve for your site: flat up to about 1.3–1.4, then steep.
  • Hours at each loading reveals how rarely the inverter works near full power: most of its hours are below 50% load.
  • Lost value (NPV) versus inverter saving in the size table shows the money behind the recommendation.

Typical values

Situation Typical DC/AC ratio Expected clipping
South-facing, sunny, hot climate 1.1–1.25 < 1%
South-facing, central/northern Europe 1.2–1.35 < 1%
East–west roof, 10–15° tilt 1.3–1.5 < 1%
Utility single-axis tracking 1.2–1.35 1–3%
Grid-capped home (e.g. 3.68 kW limit) 1.3–1.7 0.5–5%
Battery-coupled hybrid (DC-coupled storage) 1.4–2.0 captured by battery

Tips

  • Don’t oversize the inverter. A ratio below 1.0 wastes money and lowers efficiency at the low loads where the inverter spends most of its time.
  • East–west and steep arrays tolerate higher ratios, because the two faces peak at different times and neither receives full sun.
  • Mind the grid limit. If your utility caps export or inverter size, a higher DC/AC ratio is the cheapest way to get more energy within the cap; a DC-coupled battery can absorb what would be clipped.
  • Check current per MPPT. A large array on a small inverter can exceed the input current per tracker; verify with the string sizing calculator.
  • Size the AC cable for the inverter’s maximum current, not for the average output; see the cable size calculator.

Limitations

Hourly averages smooth out brief irradiance peaks caused by cloud edges, which can push arrays above their hourly maximum for minutes at a time; studies using one-minute data find roughly 1.5–2× more clipping than hourly models at high DC/AC ratios. The inverter efficiency is treated as constant, temperature derating of the inverter in hot enclosures is not modelled, and the export-limit option assumes a constant daytime house load. Results are for one weather year; check others with the weather-year option.

Method & assumptions

The array's DC output is simulated for every hour of a NASA weather year (sun position, Hay–Davies transposition, incidence and temperature losses, your DC losses). For each candidate inverter size S the hourly AC output is min(DC × η, S); the energy above S is clipped. An optional export limit caps output at limit + house load.

Economics: the energy lost by each smaller standard size is valued over the inverter's life (NPV at your discount rate) and compared with the purchase saving per kW. The recommendation is the smallest standard size clipping ≤ 0.5% (hourly), or the economic optimum if it clips ≤ 2%, within any grid limit you set.

Frequently asked questions

What size inverter do I need for my solar panels?
Most residential systems use an inverter rated at 75–90% of the array's DC power, which is a DC/AC ratio of about 1.1–1.35. For 8 kWp of south-facing panels in central or southern Europe a 6 kW inverter (ratio 1.33) loses well under 1% of annual energy to clipping. East–west arrays, steep or shaded arrays and cloudy climates can go to 1.4–1.5 because they rarely reach full power.
What is a good DC/AC ratio?
1.1–1.3 is the usual residential range; utility plants typically use 1.2–1.4, and some hybrid systems up to 1.5 or more. Above about 1.4 clipping losses climb quickly (several percent at 1.6 and 5–10% at 1.8–2.0 in sunny climates). Check the inverter datasheet: manufacturers state a maximum DC input power or ratio.
What is inverter clipping?
When the panels could deliver more power than the inverter's AC rating, the inverter moves the array off its maximum power point and caps output at its rating. The lost energy is 'clipped'. It happens on cool, clear days around noon, typically for a few dozen hours a year at a DC/AC ratio of 1.3.
Why don't solar panels produce their rated power?
Rated (STC) power assumes 1,000 W/m² of sunlight on cells at 25 °C. In real operation cells run 20–35 °C hotter, the sun is rarely perpendicular, and soiling, wiring and mismatch cost 5–15%. A typical array peaks at about 75–85% of its kWp rating, which is why undersizing the inverter costs so little.
Do I need a single-phase or three-phase inverter?
That depends on your grid connection and local rules. Many European grids cap single-phase generators at 3.68–5 kW (16–20 A) to avoid phase imbalance; above that a three-phase inverter, which spreads the current over three conductors, is required. A 10 kW three-phase inverter at 400 V draws about 14.4 A per phase, versus 43.5 A for a single-phase unit at 230 V.
Is it OK to oversize the solar array?
Yes, within the inverter's limits. Oversizing (DC/AC above 1) raises energy per inverter kW, improves morning, evening and winter output, and lowers the cost per kWh. The constraints are the inverter's maximum DC input power, MPPT current per input and maximum DC voltage, so check the string design with the solar string sizing calculator.

Sources & references

  1. Good, J. & Johnson, J.X. (2016). Impact of inverter loading ratio on solar photovoltaic system performance. Applied Energy 177
  2. NREL — PVWatts Version 5 Manual (DC/AC ratio and inverter model), NREL/TP-6A20-62641
  3. Lawrence Berkeley National Laboratory — Utility-Scale Solar (inverter loading ratio trends)
  4. NASA POWER — hourly solar and meteorological data

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