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Batteries & storage calculator

Pumped hydro storage calculator

Turns reservoir volume, head and machine efficiencies into MWh stored, round-trip efficiency, hours of discharge, drawdown, arbitrage revenue and levelized cost of storage.

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Results

This reservoir pair stores 2.4 GWh of deliverable electricity (7.9 hours at 300 MW) with a round-trip efficiency of 75.7%, a typical daily-cycling duration. Each cubic metre holds 0.95 kWh, so head matters as much as volume. Arbitrage alone does not cover the levelized cost (119 vs 110 €/MWh); real plants also earn from capacity and grid services.
Energy delivered per full cycle
2.4GWh
3,147 MWh needed to pump it up
Round-trip efficiency
75.7%
generating 87.5% · pumping 86.6%
Discharge time
7.9h
at 300 MW, flow 87 m³/s
Charge time
10.5h
at 300 MW pumping
Gravitational energy (ideal)
2,725MWh
ρ·g·V·H, before losses
Reservoir drawdown
6.3m
1.6% of head; power stays steady below about 15%
Olympic pools
1,000
0.95 kWh per m³ of water
Arbitrage margin / yr
€36,164,992
300 cycles · spread 65 €/MWh
LCOS (incl. charging)
119€/MWh
capital + O&M alone 60 €/MWh
Simple payback
18 yr 11 mo
capex 600 M€
Equivalent battery containers
611
≈3.9 MWh per utility battery container
Where the pumping energy goes
Deliverable energy of your volume at other heads

Real pumped-storage plants for comparison (approximate)

PlantPower (MW)Storage (GWh)Head (m)Hours
Your design3002.384007.9
Dinorwig, UK1,728~9~500~5
Goldisthal, Germany1,060~8.5~300~8
Bath County, USA~3,000~24~380~8–11
Cruachan, UK440~7~365~16
  • Head varies as the reservoirs fill and empty; this model uses the mean head. Large drawdown relative to head reduces power and efficiency at the end of discharge.
  • Evaporation, seepage and environmental flow constraints are ignored. Revenue counts energy arbitrage only; ancillary services (frequency response, inertia, reserve) often earn as much again.

How this pumped hydro calculator works

Pumped storage hydropower (PSH) is a giant rechargeable battery made of two reservoirs at different heights. When electricity is cheap or abundant, pumps lift water to the upper reservoir; when it is needed, the water flows back down through turbines. What it stores is the gravitational potential energy of the water, so volume and height difference (head) count in equal measure.

The calculator takes the usable volume, gross head and machine ratings and computes:

  • the ideal gravitational energy and the electricity actually delivered after hydraulic, turbine, generator and transformer losses;
  • the electricity needed to pump the water back up, and hence the round-trip efficiency;
  • discharge and charge hours at the turbine and pump power, and the flow rate;
  • drawdown of the upper reservoir and an Olympic-pool comparison;
  • arbitrage revenue, simple payback and levelized cost of storage (LCOS), with the number of cycles capped to what the charge and discharge times physically allow.

The formulas

E_ideal (MWh) = ρ × g × V × H / 3.6×10⁹ E_out = E_ideal × (1 − h_loss) × η_turbine × η_generator × η_transformer E_in = E_ideal × (1 + h_loss) / (η_pump × η_motor × η_transformer) Round-trip efficiency = E_out / E_in Discharge hours = E_out / P_turbine Charge hours = E_in / P_pump LCOS = (Capex × CRF + fixed O&M + cost of charging energy) / annual MWh delivered

ρ = 1,000 kg/m³, g = 9.81 m/s², V in m³, H in m, h_loss = hydraulic losses as a fraction of head (each way).

Worked example: a 300 MW, 8-hour plant

The defaults describe an upper reservoir holding 2.5 million m³ of usable water (1,000 Olympic pools), 400 m above the lower reservoir, with reversible units of 300 MW:

  • ideal stored energy: 1,000 × 9.81 × 2.5×10⁶ × 400 / 3.6×10⁹ ≈ 2,725 MWh;
  • with 3% hydraulic loss each way, a 92% turbine, 91% pump, 98.5% motor-generator and 99.5% transformer efficiency, it delivers 2,380 MWh and needs 3,150 MWh to refill, a round-trip efficiency of about 76%;
  • that is 7.9 hours at full power and 10.5 hours of pumping; the 40-hectare upper reservoir drops by about 6 m, small relative to the head;
  • each cubic metre is worth about 0.95 kWh of delivered electricity.

Buying at €45/MWh and selling at €110/MWh for 300 cycles a year earns an arbitrage margin of about €36 million. With €2,000/kW capex (€600 million) the simple payback is around 19 years, and the LCOS including charging energy (about €119/MWh) sits slightly above the selling price. That is normal. Real plants also earn capacity payments and grid-service revenue (reserves, frequency response, inertia, black start), which this simple arbitrage view excludes.

How to read the results

  • Energy delivered per cycle is the usable storage capacity at the grid connection.
  • Round-trip efficiency: every MWh delivered costs 1/RTE MWh of charging electricity. At 76% efficiency the price spread must exceed about 24% of the selling price just to cover the losses.
  • Discharge time decides which services the plant can sell. Daily cycling needs 4–10 hours; weekly or seasonal shifting needs much more.
  • Drawdown: if the water level falls a lot relative to head, the head at the end of discharge is lower, and so are power and efficiency.
  • LCOS vs capital-only cost: the gap is what you pay for the energy that charges the plant.

Typical values

Parameter Typical range
Gross head 100–800 m (best 300–700 m)
Round-trip efficiency 70–82%
Discharge duration 6–12 h (some > 20 h)
Unit size 100–400 MW per reversible unit
Capex 1,500–3,500 per kW
Design life 50–100 years
Response time ~1–2 minutes from standstill; seconds when spinning

Well-known examples: Dinorwig (UK, ~1.7 GW, ~9 GWh, ~500 m head), Goldisthal (Germany, ~1.06 GW, ~8.5 GWh, ~300 m) and Bath County (USA, ~3 GW, one of the largest in the world).

Tips

  • Head beats volume. Doubling the head doubles the energy for the same dam, tunnel diameter and water volume, which is why high-head sites are much cheaper per MWh.
  • Look for existing reservoirs. Pairing an existing lake or a former mine pit with a new reservoir cuts cost and environmental impact.
  • Size power and energy separately. Turbines set MW, reservoirs set MWh; adding volume is often cheap compared with adding machines.
  • Variable-speed units can regulate power while pumping, earning more from grid services.
  • Compare with other options using the LCOE calculator and convert units with the energy unit converter.

Limitations

The model uses a single mean head; real head varies as reservoirs fill and empty. Evaporation, seepage, environmental flow obligations, ramp limits and outages are not modelled. Revenue covers energy arbitrage at a flat price spread only, and the cycle count is capped by charge and discharge time but not by market reality; actual plants rarely complete a full cycle every day. Capital costs are highly site-specific, dominated by tunnels, dams and geology.

Method & assumptions

Stored energy: E = ρ · g · V · H (J) ÷ 3.6×10⁹ = MWh, with ρ = 1,000 kg/m³ and g = 9.81 m/s². Generating delivers E · (1 − hloss) · ηturbine · ηgenerator · ηtransformer; pumping needs E · (1 + hloss) ÷ (ηpump · ηmotor · ηtransformer). Round-trip efficiency = delivered ÷ pumped (typically 70–82%). Discharge hours = delivered MWh ÷ turbine MW. LCOS = (capex × CRF + fixed O&M + charging cost) ÷ annual MWh delivered.

Frequently asked questions

How much energy can pumped hydro store?
E = ρ × g × V × H × η. One cubic metre of water lifted 100 m stores 0.27 kWh before losses; at 400 m it is about 1.1 kWh, of which roughly 0.95 kWh comes back as electricity. A reservoir of 2.5 million m³ with 400 m of head therefore delivers about 2.4 GWh per cycle.
What is the round-trip efficiency of pumped hydro?
Typically 70–82% for modern plants with reversible pump-turbines; older plants are closer to 65–75%. Losses come from the pump and motor (about 9–12%), the turbine and generator (8–10%), friction in tunnels and penstocks (2–5% each way) and transformers.
How long can a pumped hydro plant generate?
Most plants are designed for 6–12 hours at full power, some for over 20 hours. Duration = stored energy ÷ turbine power, so the same reservoirs can be built as a short, powerful plant or a long, lower-power one.
How much does pumped hydro storage cost?
Capital costs are typically 1,500–3,500 per kW (EUR or USD) for plants with 6–12 hours of storage, i.e. roughly 150–400 per kWh of capacity. At long durations that is far cheaper per kWh than batteries, though projects take years to build and need the right site. Lifetimes of 50–100 years are normal.
Is pumped hydro better than batteries?
For long durations (6+ hours), very large scale and decades of service, pumped hydro is usually cheaper per kWh and does not degrade with cycling. Batteries win for short durations (1–4 hours), fast response, modular deployment and sites without suitable topography.
How much of the world's energy storage is pumped hydro?
Pumped hydro still accounts for the large majority of installed electricity storage energy capacity worldwide (roughly 180–200 GW of power capacity), although batteries are now growing much faster in new installations.

Sources & references

  1. IEA — Hydropower Special Market Report (2021)
  2. International Hydropower Association — Pumped storage hydropower
  3. Blakers, A., Stocks, M., Lu, B., Cheng, C. (2021). A review of pumped hydro energy storage. Progress in Energy 3(2)
  4. Mongird, K. et al. (2020). Energy Storage Grand Challenge Cost and Performance Assessment. PNNL / US DOE

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